1/2(2+a)=1/3^2(3a+4)

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Solution for 1/2(2+a)=1/3^2(3a+4) equation: 



1/2(2+a)=1/3^2(3a+4)

We move all terms to the left:

1/2(2+a)-(1/3^2(3a+4))=0



Domain of the equation: 2(2+a)!=0

a∈R





Domain of the equation: 3^2(3a+4))!=0

a∈R



We add all the numbers together, and all the variables

1/2(a+2)-(1/3^2(3a+4))=0

We calculate fractions


(3a^23/(2(a+2)*3^2(3a+4)))+(-2aa/(2(a+2)*3^2(3a+4)))=0



We calculate terms in parentheses: +(3a^23/(2(a+2)*3^2(3a+4))), so:

3a^23/(2(a+2)*3^2(3a+4))

We do not support eapression: a^23

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